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13000122132227 is a prime number
BaseRepresentation
bin1011110100101101001110…
…1010010110011100000011
31201000210120212022111012022
42331023103222112130003
53200443222231212402
643352101302152055
72511141100613126
oct275132352263403
951023525274168
1013000122132227
11416235903851a
12155b61672262b
13733ba207a9c9
1432d2d03383bd
1517826a25e2a2
hexbd2d3a96703

13000122132227 has 2 divisors, whose sum is σ = 13000122132228. Its totient is φ = 13000122132226.

The previous prime is 13000122132211. The next prime is 13000122132253. The reversal of 13000122132227 is 72223122100031.

It is an a-pointer prime, because the next prime (13000122132253) can be obtained adding 13000122132227 to its sum of digits (26).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13000122132227 - 24 = 13000122132211 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13000122132196 and 13000122132205.

It is not a weakly prime, because it can be changed into another prime (13000122632227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500061066113 + 6500061066114.

It is an arithmetic number, because the mean of its divisors is an integer number (6500061066114).

Almost surely, 213000122132227 is an apocalyptic number.

13000122132227 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000122132227 is an equidigital number, since it uses as much as digits as its factorization.

13000122132227 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 26.

Adding to 13000122132227 its reverse (72223122100031), we get a palindrome (85223244232258).

The spelling of 13000122132227 in words is "thirteen trillion, one hundred twenty-two million, one hundred thirty-two thousand, two hundred twenty-seven".