Base | Representation |
---|---|
bin | 111100100010010101… |
… | …1101001101000101100 |
3 | 110102120000101220202112 |
4 | 1321010223221220230 |
5 | 4112220313443200 |
6 | 135415523143152 |
7 | 12251360631206 |
oct | 1710453515054 |
9 | 412500356675 |
10 | 130001312300 |
11 | 50151396082 |
12 | 21241214ab8 |
13 | c34a243c42 |
14 | 641372b776 |
15 | 35ad022535 |
hex | 1e44ae9a2c |
130001312300 has 18 divisors (see below), whose sum is σ = 282102847908. Its totient is φ = 52000524880.
The previous prime is 130001312299. The next prime is 130001312339. The reversal of 130001312300 is 3213100031.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 650006462 + ... + 650006661.
Almost surely, 2130001312300 is an apocalyptic number.
130001312300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130001312300 is an abundant number, since it is smaller than the sum of its proper divisors (152101535608).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130001312300 is a wasteful number, since it uses less digits than its factorization.
130001312300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1300013137 (or 1300013130 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 130001312300 its reverse (3213100031), we get a palindrome (133214412331).
The spelling of 130001312300 in words is "one hundred thirty billion, one million, three hundred twelve thousand, three hundred".
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