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1300013149 is a prime number
BaseRepresentation
bin100110101111100…
…1010000001011101
310100121012111210011
41031133022001131
510130300410044
6332555443221
744133633541
oct11537120135
93317174704
101300013149
11607907136
12303456511
13179440c66
14c4925a21
15791e4134
hex4d7ca05d

1300013149 has 2 divisors, whose sum is σ = 1300013150. Its totient is φ = 1300013148.

The previous prime is 1300013129. The next prime is 1300013173. The reversal of 1300013149 is 9413100031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 692637124 + 607376025 = 26318^2 + 24645^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300013149 - 213 = 1300004957 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300013119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650006574 + 650006575.

It is an arithmetic number, because the mean of its divisors is an integer number (650006575).

Almost surely, 21300013149 is an apocalyptic number.

It is an amenable number.

1300013149 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300013149 is an equidigital number, since it uses as much as digits as its factorization.

1300013149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 22.

The square root of 1300013149 is about 36055.6950980008. The cubic root of 1300013149 is about 1091.3965627218.

The spelling of 1300013149 in words is "one billion, three hundred million, thirteen thousand, one hundred forty-nine".