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1300013201211 = 3433337733737
BaseRepresentation
bin10010111010101110110…
…100110011011100111011
311121021120011012010212220
4102322232310303130323
5132244411334414321
62433115014335123
7162631352613024
oct22725664633473
94537504163786
101300013201211
1146137261948a
1218bb4b95a4a3
139578aa6a0ca
1446cc7223c4b
1523c3a1819c6
hex12eaed3373b

1300013201211 has 4 divisors (see below), whose sum is σ = 1733350934952. Its totient is φ = 866675467472.

The previous prime is 1300013201183. The next prime is 1300013201239. The reversal of 1300013201211 is 1121023100031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1300013201183) and next prime (1300013201239).

It is a cyclic number.

It is not a de Polignac number, because 1300013201211 - 26 = 1300013201147 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1300013206211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216668866866 + ... + 216668866871.

It is an arithmetic number, because the mean of its divisors is an integer number (433337733738).

Almost surely, 21300013201211 is an apocalyptic number.

1300013201211 is a deficient number, since it is larger than the sum of its proper divisors (433337733741).

1300013201211 is an equidigital number, since it uses as much as digits as its factorization.

1300013201211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 433337733740.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 1300013201211 its reverse (1121023100031), we get a palindrome (2421036301242).

The spelling of 1300013201211 in words is "one trillion, three hundred billion, thirteen million, two hundred one thousand, two hundred eleven".

Divisors: 1 3 433337733737 1300013201211