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1300013201239 is a prime number
BaseRepresentation
bin10010111010101110110…
…100110011011101010111
311121021120011012010220221
4102322232310303131113
5132244411334414424
62433115014335211
7162631352613064
oct22725664633527
94537504163827
101300013201239
11461372619505
1218bb4b95a507
139578aa6a11c
1446cc7223c6b
1523c3a1819e4
hex12eaed33757

1300013201239 has 2 divisors, whose sum is σ = 1300013201240. Its totient is φ = 1300013201238.

The previous prime is 1300013201183. The next prime is 1300013201257. The reversal of 1300013201239 is 9321023100031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1300013201239 - 213 = 1300013193047 is a prime.

It is a super-2 number, since 2×13000132012392 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300013201339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650006600619 + 650006600620.

It is an arithmetic number, because the mean of its divisors is an integer number (650006600620).

Almost surely, 21300013201239 is an apocalyptic number.

1300013201239 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300013201239 is an equidigital number, since it uses as much as digits as its factorization.

1300013201239 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 25.

The spelling of 1300013201239 in words is "one trillion, three hundred billion, thirteen million, two hundred one thousand, two hundred thirty-nine".