Base | Representation |
---|---|
bin | 10010111010101110110… |
… | …100110011011101010111 |
3 | 11121021120011012010220221 |
4 | 102322232310303131113 |
5 | 132244411334414424 |
6 | 2433115014335211 |
7 | 162631352613064 |
oct | 22725664633527 |
9 | 4537504163827 |
10 | 1300013201239 |
11 | 461372619505 |
12 | 18bb4b95a507 |
13 | 9578aa6a11c |
14 | 46cc7223c6b |
15 | 23c3a1819e4 |
hex | 12eaed33757 |
1300013201239 has 2 divisors, whose sum is σ = 1300013201240. Its totient is φ = 1300013201238.
The previous prime is 1300013201183. The next prime is 1300013201257. The reversal of 1300013201239 is 9321023100031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1300013201239 - 213 = 1300013193047 is a prime.
It is a super-2 number, since 2×13000132012392 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1300013201339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650006600619 + 650006600620.
It is an arithmetic number, because the mean of its divisors is an integer number (650006600620).
Almost surely, 21300013201239 is an apocalyptic number.
1300013201239 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300013201239 is an equidigital number, since it uses as much as digits as its factorization.
1300013201239 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 25.
The spelling of 1300013201239 in words is "one trillion, three hundred billion, thirteen million, two hundred one thousand, two hundred thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.099 sec. • engine limits •