1300013206211 has 2 divisors, whose sum is σ = 1300013206212. Its totient is φ = 1300013206210.

The previous prime is 1300013206189. The next prime is 1300013206213. The reversal of 1300013206211 is 1126023100031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1300013206211 is a prime.

Together with 1300013206213, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1300013206213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650006603105 + 650006603106.

It is an arithmetic number, because the mean of its divisors is an integer number (650006603106).

Almost surely, 2^{1300013206211} is an apocalyptic number.

1300013206211 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300013206211 is an equidigital number, since it uses as much as digits as its factorization.

1300013206211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 1300013206211 its reverse (1126023100031), we get a palindrome (2426036306242).

The spelling of 1300013206211 in words is "one trillion, three hundred billion, thirteen million, two hundred six thousand, two hundred eleven".