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1300013524542 = 23239420387859
BaseRepresentation
bin10010111010101110110…
…110000010011000111110
311121021120011210120102010
4102322232312002120332
5132244411430241132
62433115025312050
7162631355430465
oct22725666023076
94537504716363
101300013524542
1146137281a3a7
1218bb4ba95626
139578ab51325
1446cc72a99dc
1523c3a1e76cc
hex12eaed8263e

1300013524542 has 16 divisors (see below), whose sum is σ = 2713071703680. Its totient is φ = 414497065752.

The previous prime is 1300013524529. The next prime is 1300013524573. The reversal of 1300013524542 is 2454253100031.

It is a super-2 number, since 2×13000135245422 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4710193792 + ... + 4710194067.

It is an arithmetic number, because the mean of its divisors is an integer number (169566981480).

Almost surely, 21300013524542 is an apocalyptic number.

1300013524542 is an abundant number, since it is smaller than the sum of its proper divisors (1413058179138).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300013524542 is a wasteful number, since it uses less digits than its factorization.

1300013524542 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9420387887.

The product of its (nonzero) digits is 14400, while the sum is 30.

Adding to 1300013524542 its reverse (2454253100031), we get a palindrome (3754266624573).

The spelling of 1300013524542 in words is "one trillion, three hundred billion, thirteen million, five hundred twenty-four thousand, five hundred forty-two".

Divisors: 1 2 3 6 23 46 69 138 9420387859 18840775718 28261163577 56522327154 216668920757 433337841514 650006762271 1300013524542