Base | Representation |
---|---|
bin | 1011110100101101010101… |
… | …1110110001100101011101 |
3 | 1201000210122222202001121220 |
4 | 2331023111132301211131 |
5 | 3200443303034332000 |
6 | 43352104312243553 |
7 | 2511141621205332 |
oct | 275132536614535 |
9 | 51023588661556 |
10 | 13000152652125 |
11 | 4162374293581 |
12 | 155b6249a05b9 |
13 | 733ba84a5512 |
14 | 32d2d4400989 |
15 | 17826cc8c1a0 |
hex | bd2d57b195d |
13000152652125 has 64 divisors (see below), whose sum is σ = 22090193199360. Its totient is φ = 6787614720000.
The previous prime is 13000152652117. The next prime is 13000152652133. The reversal of 13000152652125 is 52125625100031.
It is an interprime number because it is at equal distance from previous prime (13000152652117) and next prime (13000152652133).
It is not a de Polignac number, because 13000152652125 - 23 = 13000152652117 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 4113085 + ... + 6551165.
It is an arithmetic number, because the mean of its divisors is an integer number (345159268740).
Almost surely, 213000152652125 is an apocalyptic number.
13000152652125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13000152652125 is a deficient number, since it is larger than the sum of its proper divisors (9090040547235).
13000152652125 is a wasteful number, since it uses less digits than its factorization.
13000152652125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2438399 (or 2438389 counting only the distinct ones).
The product of its (nonzero) digits is 18000, while the sum is 33.
Adding to 13000152652125 its reverse (52125625100031), we get a palindrome (65125777752156).
The spelling of 13000152652125 in words is "thirteen trillion, one hundred fifty-two million, six hundred fifty-two thousand, one hundred twenty-five".
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