13000198084303 has 2 divisors, whose sum is σ = 13000198084304. Its totient is φ = 13000198084302.

The previous prime is 13000198084283. The next prime is 13000198084309. The reversal of 13000198084303 is 30348089100031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13000198084303 is a prime.

It is a super-2 number, since 2×13000198084303² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13000198084309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500099042151 + 6500099042152.

It is an arithmetic number, because the mean of its divisors is an integer number (6500099042152).

Almost surely, 2^{13000198084303} is an apocalyptic number.

13000198084303 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000198084303 is an equidigital number, since it uses as much as digits as its factorization.

13000198084303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 62208, while the sum is 40.

The spelling of 13000198084303 in words is "thirteen trillion, one hundred ninety-eight million, eighty-four thousand, three hundred three".