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13000203250421 is a prime number
BaseRepresentation
bin1011110100101101100001…
…1111110010101011110101
31201000210210111221201102212
42331023120133302223311
53200443404013003141
643352113320543205
72511143104244252
oct275133037625365
951023714851385
1013000203250421
11416239a902852
12155b639921b05
13733bb5b1003a
1432d2db012429
151782724342eb
hexbd2d87f2af5

13000203250421 has 2 divisors, whose sum is σ = 13000203250422. Its totient is φ = 13000203250420.

The previous prime is 13000203250351. The next prime is 13000203250429. The reversal of 13000203250421 is 12405230200031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10037808062500 + 2962395187921 = 3168250^2 + 1721161^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13000203250421 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13000203250429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500101625210 + 6500101625211.

It is an arithmetic number, because the mean of its divisors is an integer number (6500101625211).

Almost surely, 213000203250421 is an apocalyptic number.

It is an amenable number.

13000203250421 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000203250421 is an equidigital number, since it uses as much as digits as its factorization.

13000203250421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 13000203250421 its reverse (12405230200031), we get a palindrome (25405433450452).

The spelling of 13000203250421 in words is "thirteen trillion, two hundred three million, two hundred fifty thousand, four hundred twenty-one".