1300021100311 has 2 divisors, whose sum is σ = 1300021100312. Its totient is φ = 1300021100310.

The previous prime is 1300021100267. The next prime is 1300021100369. The reversal of 1300021100311 is 1130011200031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1300021100311 - 2¹⁷ = 1300020969239 is a prime.

It is a super-2 number, since 2×1300021100311² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1300021100291 and 1300021100300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300021100011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650010550155 + 650010550156.

It is an arithmetic number, because the mean of its divisors is an integer number (650010550156).

Almost surely, 2^{1300021100311} is an apocalyptic number.

1300021100311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300021100311 is an equidigital number, since it uses as much as digits as its factorization.

1300021100311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1300021100311 its reverse (1130011200031), we get a palindrome (2430032300342).

The spelling of 1300021100311 in words is "one trillion, three hundred billion, twenty-one million, one hundred thousand, three hundred eleven".