Base | Representation |
---|---|
bin | 111100100010010111… |
… | …1001010011100110100 |
3 | 110102120002010200220201 |
4 | 1321010233022130310 |
5 | 4112221032430030 |
6 | 135415555010244 |
7 | 12251401514653 |
oct | 1710457123464 |
9 | 412502120821 |
10 | 130002233140 |
11 | 501519649aa |
12 | 21241599984 |
13 | c34a4a7110 |
14 | 64138cb19a |
15 | 35ad1552ca |
hex | 1e44bca734 |
130002233140 has 48 divisors (see below), whose sum is σ = 294120046080. Its totient is φ = 47982049920.
The previous prime is 130002233131. The next prime is 130002233149. The reversal of 130002233140 is 41332200031.
It is an interprime number because it is at equal distance from previous prime (130002233131) and next prime (130002233149).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130002233149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 577171 + ... + 770149.
It is an arithmetic number, because the mean of its divisors is an integer number (6127500960).
Almost surely, 2130002233140 is an apocalyptic number.
130002233140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130002233140 is an abundant number, since it is smaller than the sum of its proper divisors (164117812940).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130002233140 is a wasteful number, since it uses less digits than its factorization.
130002233140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 195592 (or 195590 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 130002233140 its reverse (41332200031), we get a palindrome (171334433171).
It can be divided in two parts, 13000 and 2233140, that added together give a triangular number (2246140 = T2119).
The spelling of 130002233140 in words is "one hundred thirty billion, two million, two hundred thirty-three thousand, one hundred forty".
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