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13000224130009 is a prime number
BaseRepresentation
bin1011110100101101100110…
…1111011100001111011001
31201000210211222020111211221
42331023121233130033121
53200443424334130014
643352115344252041
72511143446565554
oct275133157341731
951023758214757
1013000224130009
114162400673a06
12155b644911021
13733bba24091c
1432d2ddac969b
151782741aab24
hexbd2d9bdc3d9

13000224130009 has 2 divisors, whose sum is σ = 13000224130010. Its totient is φ = 13000224130008.

The previous prime is 13000224129911. The next prime is 13000224130037. The reversal of 13000224130009 is 90003142200031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12126273998400 + 873950131609 = 3482280^2 + 934853^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13000224130009 is a prime.

It is a super-3 number, since 3×130002241300093 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13000224130409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500112065004 + 6500112065005.

It is an arithmetic number, because the mean of its divisors is an integer number (6500112065005).

Almost surely, 213000224130009 is an apocalyptic number.

It is an amenable number.

13000224130009 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000224130009 is an equidigital number, since it uses as much as digits as its factorization.

13000224130009 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

The spelling of 13000224130009 in words is "thirteen trillion, two hundred twenty-four million, one hundred thirty thousand, nine".