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13000302120000 = 263541329674289
BaseRepresentation
bin1011110100101101111001…
…1000111100110001000000
31201000211001101222211000010
42331023132120330301000
53200444104320320000
643352131212024520
72511145414520616
oct275133630746100
951024041884003
1013000302120000
1141624406a1a48
12155b666a62140
13733c00449150
1432d30a1cb6b6
1517827ae63d50
hexbd2de63cc40

13000302120000 has 1120 divisors, whose sum is σ = 48610517155200. Its totient is φ = 3042902016000.

The previous prime is 13000302119977. The next prime is 13000302120019. The reversal of 13000302120000 is 2120300031.

It is a happy number.

13000302120000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×130003021200002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 3031077856 + ... + 3031082144.

It is an arithmetic number, because the mean of its divisors is an integer number (43402247460).

Almost surely, 213000302120000 is an apocalyptic number.

13000302120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13000302120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24305258577600).

13000302120000 is an abundant number, since it is smaller than the sum of its proper divisors (35610215035200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13000302120000 is a wasteful number, since it uses less digits than its factorization.

13000302120000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4433 (or 4408 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 12.

Adding to 13000302120000 its reverse (2120300031), we get a palindrome (13002422420031).

The spelling of 13000302120000 in words is "thirteen trillion, three hundred two million, one hundred twenty thousand".