Search a number
-
+
1300030477 = 17312466851
BaseRepresentation
bin100110101111100…
…1110010000001101
310100121020101112221
41031133032100031
510130301433402
6333000055341
744134035214
oct11537162015
93317211487
101300030477
11607919159
12303464551
13179448b05
14c492c07b
15791e9337
hex4d7ce40d

1300030477 has 8 divisors (see below), whose sum is σ = 1420906752. Its totient is φ = 1184088000.

The previous prime is 1300030469. The next prime is 1300030499. The reversal of 1300030477 is 7740300031.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1300030477 - 23 = 1300030469 is a prime.

It is a super-2 number, since 2×13000304772 = 3380158482257695058, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300030427) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1232899 + ... + 1233952.

It is an arithmetic number, because the mean of its divisors is an integer number (177613344).

Almost surely, 21300030477 is an apocalyptic number.

1300030477 is a gapful number since it is divisible by the number (17) formed by its first and last digit.

It is an amenable number.

1300030477 is a deficient number, since it is larger than the sum of its proper divisors (120876275).

1300030477 is a wasteful number, since it uses less digits than its factorization.

1300030477 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2466899.

The product of its (nonzero) digits is 1764, while the sum is 25.

The square root of 1300030477 is about 36055.9353921099. The cubic root of 1300030477 is about 1091.4014118101.

The spelling of 1300030477 in words is "one billion, three hundred million, thirty thousand, four hundred seventy-seven".

Divisors: 1 17 31 527 2466851 41936467 76472381 1300030477