Base | Representation |
---|---|
bin | 11101100011110010110100… |
… | …101010110010101110001101 |
3 | 122001022011201122112012022202 |
4 | 131203302310222302232031 |
5 | 114014432322403411023 |
6 | 1140254333352051245 |
7 | 36245262016560302 |
oct | 3543626452625615 |
9 | 561264648465282 |
10 | 130003101232013 |
11 | 38472007520799 |
12 | 126b757b693b25 |
13 | 5770316c21c09 |
14 | 241627ddd70a9 |
15 | 1006a2b987128 |
hex | 763cb4ab2b8d |
130003101232013 has 2 divisors, whose sum is σ = 130003101232014. Its totient is φ = 130003101232012.
The previous prime is 130003101231943. The next prime is 130003101232019. The reversal of 130003101232013 is 310232101300031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 100309298795209 + 29693802436804 = 10015453^2 + 5449202^2 .
It is a cyclic number.
It is not a de Polignac number, because 130003101232013 - 218 = 130003100969869 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130003101232019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65001550616006 + 65001550616007.
It is an arithmetic number, because the mean of its divisors is an integer number (65001550616007).
Almost surely, 2130003101232013 is an apocalyptic number.
It is an amenable number.
130003101232013 is a deficient number, since it is larger than the sum of its proper divisors (1).
130003101232013 is an equidigital number, since it uses as much as digits as its factorization.
130003101232013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 130003101232013 its reverse (310232101300031), we get a palindrome (440235202532044).
The spelling of 130003101232013 in words is "one hundred thirty trillion, three billion, one hundred one million, two hundred thirty-two thousand, thirteen".
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