13000311421 has 2 divisors, whose sum is σ = 13000311422. Its totient is φ = 13000311420.

The previous prime is 13000311409. The next prime is 13000311463. The reversal of 13000311421 is 12411300031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12631287321 + 369024100 = 112389^2 + 19210^2 .

It is a cyclic number.

It is not a de Polignac number, because 13000311421 - 2⁹ = 13000310909 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13000311395 and 13000311404.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13000311221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500155710 + 6500155711.

It is an arithmetic number, because the mean of its divisors is an integer number (6500155711).

Almost surely, 2^13000311421 is an apocalyptic number.

It is an amenable number.

13000311421 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000311421 is an equidigital number, since it uses as much as digits as its factorization.

13000311421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13000311421 its reverse (12411300031), we get a palindrome (25411611452).

The spelling of 13000311421 in words is "thirteen billion, three hundred eleven thousand, four hundred twenty-one".