1300042441 has 2 divisors, whose sum is σ = 1300042442. Its totient is φ = 1300042440.

The previous prime is 1300042439. The next prime is 1300042451. The reversal of 1300042441 is 1442400031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 686440000 + 613602441 = 26200^2 + 24771^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300042441 - 2¹ = 1300042439 is a prime.

It is a super-2 number, since 2×1300042441² = 3380220696802476962, which contains 22 as substring.

Together with 1300042439, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1300042451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650021220 + 650021221.

It is an arithmetic number, because the mean of its divisors is an integer number (650021221).

Almost surely, 2^1300042441 is an apocalyptic number.

It is an amenable number.

1300042441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300042441 is an equidigital number, since it uses as much as digits as its factorization.

1300042441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 19.

The square root of 1300042441 is about 36056.1013006121. The cubic root of 1300042441 is about 1091.4047598050.

Adding to 1300042441 its reverse (1442400031), we get a palindrome (2742442472).

The spelling of 1300042441 in words is "one billion, three hundred million, forty-two thousand, four hundred forty-one".