1300050043 has 2 divisors, whose sum is σ = 1300050044. Its totient is φ = 1300050042.

The previous prime is 1300050041. The next prime is 1300050067. The reversal of 1300050043 is 3400500031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1300050043 - 2¹ = 1300050041 is a prime.

It is a super-3 number, since 3×1300050043³ (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 1300050041, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1300049999 and 1300050026.

It is not a weakly prime, because it can be changed into another prime (1300050041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650025021 + 650025022.

It is an arithmetic number, because the mean of its divisors is an integer number (650025022).

Almost surely, 2^1300050043 is an apocalyptic number.

1300050043 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300050043 is an equidigital number, since it uses as much as digits as its factorization.

1300050043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 16.

The square root of 1300050043 is about 36056.2067195095. The cubic root of 1300050043 is about 1091.4068871312.

Adding to 1300050043 its reverse (3400500031), we get a palindrome (4700550074).

The spelling of 1300050043 in words is "one billion, three hundred million, fifty thousand, forty-three".