Base | Representation |
---|---|
bin | 11000001101110101… |
… | …11000010011100001 |
3 | 1020120001200020102111 |
4 | 30012322320103201 |
5 | 203111224001121 |
6 | 5550024315321 |
7 | 640114451362 |
oct | 140672702341 |
9 | 36501606374 |
10 | 13001000161 |
11 | 55717a8936 |
12 | 262a012b41 |
13 | 12c2662006 |
14 | 8b4949b69 |
15 | 51159d2e1 |
hex | 306eb84e1 |
13001000161 has 2 divisors, whose sum is σ = 13001000162. Its totient is φ = 13001000160.
The previous prime is 13001000147. The next prime is 13001000167. The reversal of 13001000161 is 16100010031.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12540640225 + 460359936 = 111985^2 + 21456^2 .
It is a cyclic number.
It is not a de Polignac number, because 13001000161 - 211 = 13000998113 is a prime.
It is not a weakly prime, because it can be changed into another prime (13001000167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500500080 + 6500500081.
It is an arithmetic number, because the mean of its divisors is an integer number (6500500081).
Almost surely, 213001000161 is an apocalyptic number.
It is an amenable number.
13001000161 is a deficient number, since it is larger than the sum of its proper divisors (1).
13001000161 is an equidigital number, since it uses as much as digits as its factorization.
13001000161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 13001000161 its reverse (16100010031), we get a palindrome (29101010192).
The spelling of 13001000161 in words is "thirteen billion, one million, one hundred sixty-one", and thus it is an aban number.
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