130010011003 has 2 divisors, whose sum is σ = 130010011004. Its totient is φ = 130010011002.

The previous prime is 130010010989. The next prime is 130010011007. The reversal of 130010011003 is 300110010031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130010011003 - 2²⁹ = 129473140091 is a prime.

It is a super-2 number, since 2×130010011003² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130010011007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005005501 + 65005005502.

It is an arithmetic number, because the mean of its divisors is an integer number (65005005502).

Almost surely, 2^130010011003 is an apocalyptic number.

130010011003 is a deficient number, since it is larger than the sum of its proper divisors (1).

130010011003 is an equidigital number, since it uses as much as digits as its factorization.

130010011003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 10.

Adding to 130010011003 its reverse (300110010031), we get a palindrome (430120021034).

The spelling of 130010011003 in words is "one hundred thirty billion, ten million, eleven thousand, three".