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130010011314 = 2350849426131
BaseRepresentation
bin111100100010100110…
…0110101011010110010
3110102120121202212120020
41321011030311122302
54112230030330224
6135420433424310
712251524601601
oct1710514653262
9412517685506
10130010011314
1150156297847
122124410b096
13c34bc9b5a1
146414953a38
1535adb8ec79
hex1e453356b2

130010011314 has 16 divisors (see below), whose sum is σ = 260025746400. Its totient is φ = 43335716480.

The previous prime is 130010011289. The next prime is 130010011421. The reversal of 130010011314 is 413110010031.

It is a junction number, because it is equal to n+sod(n) for n = 130010011293 and 130010011302.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 92029 + ... + 518159.

It is an arithmetic number, because the mean of its divisors is an integer number (16251609150).

Almost surely, 2130010011314 is an apocalyptic number.

130010011314 is an abundant number, since it is smaller than the sum of its proper divisors (130015735086).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130010011314 is a wasteful number, since it uses less digits than its factorization.

130010011314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 476985.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 130010011314 its reverse (413110010031), we get a palindrome (543120021345).

The spelling of 130010011314 in words is "one hundred thirty billion, ten million, eleven thousand, three hundred fourteen".

Divisors: 1 2 3 6 50849 101698 152547 305094 426131 852262 1278393 2556786 21668335219 43336670438 65005005657 130010011314