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130010011315 = 597268061879
BaseRepresentation
bin111100100010100110…
…0110101011010110011
3110102120121202212120021
41321011030311122303
54112230030330230
6135420433424311
712251524601602
oct1710514653263
9412517685507
10130010011315
1150156297848
122124410b097
13c34bc9b5a2
146414953a39
1535adb8ec7a
hex1e453356b3

130010011315 has 8 divisors (see below), whose sum is σ = 157620385440. Its totient is φ = 102935761152.

The previous prime is 130010011289. The next prime is 130010011421. The reversal of 130010011315 is 513110010031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130010011315 - 25 = 130010011283 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 134030455 + ... + 134031424.

It is an arithmetic number, because the mean of its divisors is an integer number (19702548180).

Almost surely, 2130010011315 is an apocalyptic number.

130010011315 is a deficient number, since it is larger than the sum of its proper divisors (27610374125).

130010011315 is an equidigital number, since it uses as much as digits as its factorization.

130010011315 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 268061981.

The product of its (nonzero) digits is 45, while the sum is 16.

Adding to 130010011315 its reverse (513110010031), we get a palindrome (643120021346).

The spelling of 130010011315 in words is "one hundred thirty billion, ten million, eleven thousand, three hundred fifteen".

Divisors: 1 5 97 485 268061879 1340309395 26002002263 130010011315