130010011421 has 2 divisors, whose sum is σ = 130010011422. Its totient is φ = 130010011420.

The previous prime is 130010011289. The next prime is 130010011471. The reversal of 130010011421 is 124110010031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83643002521 + 46367008900 = 289211^2 + 215330^2 .

It is a cyclic number.

It is not a de Polignac number, because 130010011421 - 2³⁰ = 128936269597 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130010011396 and 130010011405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130010011471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005005710 + 65005005711.

It is an arithmetic number, because the mean of its divisors is an integer number (65005005711).

Almost surely, 2^130010011421 is an apocalyptic number.

It is an amenable number.

130010011421 is a deficient number, since it is larger than the sum of its proper divisors (1).

130010011421 is an equidigital number, since it uses as much as digits as its factorization.

130010011421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 130010011421 its reverse (124110010031), we get a palindrome (254120021452).

The spelling of 130010011421 in words is "one hundred thirty billion, ten million, eleven thousand, four hundred twenty-one".