13001001212219 has 2 divisors, whose sum is σ = 13001001212220. Its totient is φ = 13001001212218.

The previous prime is 13001001212153. The next prime is 13001001212237. The reversal of 13001001212219 is 91221210010031.

It is a strong prime.

It is an emirp because it is prime and its reverse (91221210010031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13001001212219 is a prime.

It is a super-2 number, since 2×13001001212219² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13001001212194 and 13001001212203.

It is not a weakly prime, because it can be changed into another prime (13001001242219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500500606109 + 6500500606110.

It is an arithmetic number, because the mean of its divisors is an integer number (6500500606110).

Almost surely, 2^{13001001212219} is an apocalyptic number.

13001001212219 is a deficient number, since it is larger than the sum of its proper divisors (1).

13001001212219 is an equidigital number, since it uses as much as digits as its factorization.

13001001212219 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 23.

The spelling of 13001001212219 in words is "thirteen trillion, one billion, one million, two hundred twelve thousand, two hundred nineteen".