13001001212153 has 2 divisors, whose sum is σ = 13001001212154. Its totient is φ = 13001001212152.

The previous prime is 13001001212131. The next prime is 13001001212219. The reversal of 13001001212153 is 35121210010031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12485989736704 + 515011475449 = 3533552^2 + 717643^2 .

It is a cyclic number.

It is not a de Polignac number, because 13001001212153 - 2⁸ = 13001001211897 is a prime.

It is not a weakly prime, because it can be changed into another prime (13001001212123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500500606076 + 6500500606077.

It is an arithmetic number, because the mean of its divisors is an integer number (6500500606077).

Almost surely, 2^{13001001212153} is an apocalyptic number.

It is an amenable number.

13001001212153 is a deficient number, since it is larger than the sum of its proper divisors (1).

13001001212153 is an equidigital number, since it uses as much as digits as its factorization.

13001001212153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 180, while the sum is 20.

Adding to 13001001212153 its reverse (35121210010031), we get a palindrome (48122211222184).

The spelling of 13001001212153 in words is "thirteen trillion, one billion, one million, two hundred twelve thousand, one hundred fifty-three".