1300101103319 has 2 divisors, whose sum is σ = 1300101103320. Its totient is φ = 1300101103318.

The previous prime is 1300101103291. The next prime is 1300101103333. The reversal of 1300101103319 is 9133011010031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1300101103319 - 2¹⁶ = 1300101037783 is a prime.

It is a super-2 number, since 2×1300101103319² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1300101103294 and 1300101103303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300101103019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650050551659 + 650050551660.

It is an arithmetic number, because the mean of its divisors is an integer number (650050551660).

Almost surely, 2^{1300101103319} is an apocalyptic number.

1300101103319 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300101103319 is an equidigital number, since it uses as much as digits as its factorization.

1300101103319 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243, while the sum is 23.

The spelling of 1300101103319 in words is "one trillion, three hundred billion, one hundred one million, one hundred three thousand, three hundred nineteen".