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1300101117137 is a prime number
BaseRepresentation
bin10010111010110100000…
…100001011010011010001
311121021210021121201212022
4102322310010023103101
5132300101341222022
62433131434541225
7162633501105464
oct22726404132321
94537707551768
101300101117137
11461408206a79
1218bb75297815
13957a303c574
1446cd4b8b2db
1523c42c4ac42
hex12eb410b4d1

1300101117137 has 2 divisors, whose sum is σ = 1300101117138. Its totient is φ = 1300101117136.

The previous prime is 1300101117101. The next prime is 1300101117163. The reversal of 1300101117137 is 7317111010031.

It is an a-pointer prime, because the next prime (1300101117163) can be obtained adding 1300101117137 to its sum of digits (26).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 985653825601 + 314447291536 = 992801^2 + 560756^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300101117137 - 222 = 1300096922833 is a prime.

It is not a weakly prime, because it can be changed into another prime (1300101117037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650050558568 + 650050558569.

It is an arithmetic number, because the mean of its divisors is an integer number (650050558569).

Almost surely, 21300101117137 is an apocalyptic number.

It is an amenable number.

1300101117137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300101117137 is an equidigital number, since it uses as much as digits as its factorization.

1300101117137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 441, while the sum is 26.

Adding to 1300101117137 its reverse (7317111010031), we get a palindrome (8617212127168).

The spelling of 1300101117137 in words is "one trillion, three hundred billion, one hundred one million, one hundred seventeen thousand, one hundred thirty-seven".