1300101121232 has 10 divisors (see below), whose sum is σ = 2518945922418. Its totient is φ = 650050560608.

The previous prime is 1300101121213. The next prime is 1300101121237. The reversal of 1300101121232 is 2321211010031.

It can be written as a sum of positive squares in only one way, i.e., 915075907216 + 385025214016 = 956596^2 + 620504^2 .

It is a super-2 number, since 2×1300101121232² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1300101121232.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300101121237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40628160023 + ... + 40628160054.

Almost surely, 2^{1300101121232} is an apocalyptic number.

It is an amenable number.

1300101121232 is a deficient number, since it is larger than the sum of its proper divisors (1218844801186).

1300101121232 is an equidigital number, since it uses as much as digits as its factorization.

1300101121232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81256320085 (or 81256320079 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1300101121232 its reverse (2321211010031), we get a palindrome (3621312131263).

The spelling of 1300101121232 in words is "one trillion, three hundred billion, one hundred one million, one hundred twenty-one thousand, two hundred thirty-two".