Base | Representation |
---|---|
bin | 11101100011111001010111… |
… | …000010011100110110110111 |
3 | 122001022211211211011022110111 |
4 | 131203321113002130312313 |
5 | 114020041211244411244 |
6 | 1140301454051203451 |
7 | 36245630660006143 |
oct | 3543712702346667 |
9 | 561284754138414 |
10 | 130010120310199 |
11 | 38474a89616058 |
12 | 126b89ba2a6587 |
13 | 5770b9517780c |
14 | 24167482bc223 |
15 | 1006cdccbde34 |
hex | 763e5709cdb7 |
130010120310199 has 2 divisors, whose sum is σ = 130010120310200. Its totient is φ = 130010120310198.
The previous prime is 130010120310193. The next prime is 130010120310221. The reversal of 130010120310199 is 991013021010031.
It is a weak prime.
It is an emirp because it is prime and its reverse (991013021010031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130010120310199 - 229 = 130009583439287 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130010120310199.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130010120310193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005060155099 + 65005060155100.
It is an arithmetic number, because the mean of its divisors is an integer number (65005060155100).
Almost surely, 2130010120310199 is an apocalyptic number.
130010120310199 is a deficient number, since it is larger than the sum of its proper divisors (1).
130010120310199 is an equidigital number, since it uses as much as digits as its factorization.
130010120310199 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 31.
The spelling of 130010120310199 in words is "one hundred thirty trillion, ten billion, one hundred twenty million, three hundred ten thousand, one hundred ninety-nine".
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