Base | Representation |
---|---|
bin | 111100100010100110… |
… | …1100011111111110111 |
3 | 110102120122010120021111 |
4 | 1321011031203333313 |
5 | 4112230102431403 |
6 | 135420441455451 |
7 | 12251526325045 |
oct | 1710515437767 |
9 | 412518116244 |
10 | 130010202103 |
11 | 50156408121 |
12 | 212441a1587 |
13 | c34c037392 |
14 | 64149a3395 |
15 | 35adbcb56d |
hex | 1e45363ff7 |
130010202103 has 2 divisors, whose sum is σ = 130010202104. Its totient is φ = 130010202102.
The previous prime is 130010202089. The next prime is 130010202143. The reversal of 130010202103 is 301202010031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130010202103 - 25 = 130010202071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130010202143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005101051 + 65005101052.
It is an arithmetic number, because the mean of its divisors is an integer number (65005101052).
Almost surely, 2130010202103 is an apocalyptic number.
130010202103 is a deficient number, since it is larger than the sum of its proper divisors (1).
130010202103 is an equidigital number, since it uses as much as digits as its factorization.
130010202103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 130010202103 its reverse (301202010031), we get a palindrome (431212212134).
The spelling of 130010202103 in words is "one hundred thirty billion, ten million, two hundred two thousand, one hundred three".
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