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130010311213 is a prime number
BaseRepresentation
bin111100100010100110…
…1111110101000101101
3110102120122100002221121
41321011031332220231
54112230114424323
6135420444100541
712251530261126
oct1710515765055
9412518302847
10130010311213
11501564820a2
1221244234751
13c34c074c43
1464149d104d
1535adbeda5d
hex1e4537ea2d

130010311213 has 2 divisors, whose sum is σ = 130010311214. Its totient is φ = 130010311212.

The previous prime is 130010311199. The next prime is 130010311237. The reversal of 130010311213 is 312113010031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 107048061124 + 22962250089 = 327182^2 + 151533^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130010311213 is a prime.

It is a super-2 number, since 2×1300103112132 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130010011213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005155606 + 65005155607.

It is an arithmetic number, because the mean of its divisors is an integer number (65005155607).

Almost surely, 2130010311213 is an apocalyptic number.

It is an amenable number.

130010311213 is a deficient number, since it is larger than the sum of its proper divisors (1).

130010311213 is an equidigital number, since it uses as much as digits as its factorization.

130010311213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 130010311213 its reverse (312113010031), we get a palindrome (442123321244).

The spelling of 130010311213 in words is "one hundred thirty billion, ten million, three hundred eleven thousand, two hundred thirteen".