Base | Representation |
---|---|
bin | 11101100011111001100111… |
… | …111000111110101101111010 |
3 | 122001022212120112011111000010 |
4 | 131203321213320332231322 |
5 | 114020042301134240442 |
6 | 1140301542111122350 |
7 | 36245640662116503 |
oct | 3543714770765572 |
9 | 561285515144003 |
10 | 130010403040122 |
11 | 38475114174250 |
12 | 126b8a78b133b6 |
13 | 5770c0b909927 |
14 | 2416773a77baa |
15 | 1006d07a1ab9c |
hex | 763e67e3eb7a |
130010403040122 has 48 divisors (see below), whose sum is σ = 301326407593632. Its totient is φ = 37079615834880.
The previous prime is 130010403040121. The next prime is 130010403040171. The reversal of 130010403040122 is 221040304010031.
It is not an unprimeable number, because it can be changed into a prime (130010403040121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3408033853 + ... + 3408072000.
It is an arithmetic number, because the mean of its divisors is an integer number (6277633491534).
Almost surely, 2130010403040122 is an apocalyptic number.
130010403040122 is an abundant number, since it is smaller than the sum of its proper divisors (171316004553510).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130010403040122 is a wasteful number, since it uses less digits than its factorization.
130010403040122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6816105903 (or 6816105886 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 130010403040122 its reverse (221040304010031), we get a palindrome (351050707050153).
The spelling of 130010403040122 in words is "one hundred thirty trillion, ten billion, four hundred three million, forty thousand, one hundred twenty-two".
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