1300110113 has 2 divisors, whose sum is σ = 1300110114. Its totient is φ = 1300110112.

The previous prime is 1300110103. The next prime is 1300110157. The reversal of 1300110113 is 3110110031.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1245172369 + 54937744 = 35287^2 + 7412^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300110113 - 2⁸ = 1300109857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1300110094 and 1300110103.

It is not a weakly prime, because it can be changed into another prime (1300110103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650055056 + 650055057.

It is an arithmetic number, because the mean of its divisors is an integer number (650055057).

Almost surely, 2^1300110113 is an apocalyptic number.

It is an amenable number.

1300110113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300110113 is an equidigital number, since it uses as much as digits as its factorization.

1300110113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9, while the sum is 11.

The square root of 1300110113 is about 36057.0397148740. The cubic root of 1300110113 is about 1091.4236966897.

Adding to 1300110113 its reverse (3110110031), we get a palindrome (4410220144).

The spelling of 1300110113 in words is "one billion, three hundred million, one hundred ten thousand, one hundred thirteen".