Base | Representation |
---|---|
bin | 111100100010101000… |
… | …0101001110011001111 |
3 | 110102120200122201122220 |
4 | 1321011100221303033 |
5 | 4112230304343203 |
6 | 135420511110423 |
7 | 12251536241124 |
oct | 1710520516317 |
9 | 412520581586 |
10 | 130011012303 |
11 | 50156910907 |
12 | 21244512413 |
13 | c34c25c0a3 |
14 | 6414b3474b |
15 | 35adcdb653 |
hex | 1e45429ccf |
130011012303 has 16 divisors (see below), whose sum is σ = 173905326336. Its totient is φ = 86395541760.
The previous prime is 130011012301. The next prime is 130011012347. The reversal of 130011012303 is 303210110031.
It is not a de Polignac number, because 130011012303 - 21 = 130011012301 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130011012301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2933676 + ... + 2977662.
It is an arithmetic number, because the mean of its divisors is an integer number (10869082896).
Almost surely, 2130011012303 is an apocalyptic number.
130011012303 is a deficient number, since it is larger than the sum of its proper divisors (43894314033).
130011012303 is a wasteful number, since it uses less digits than its factorization.
130011012303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47134.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 130011012303 its reverse (303210110031), we get a palindrome (433221122334).
The spelling of 130011012303 in words is "one hundred thirty billion, eleven million, twelve thousand, three hundred three".
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