Base | Representation |
---|---|
bin | 111100100010101000… |
… | …0101001110011111011 |
3 | 110102120200122201201112 |
4 | 1321011100221303323 |
5 | 4112230304343342 |
6 | 135420511110535 |
7 | 12251536241216 |
oct | 1710520516373 |
9 | 412520581645 |
10 | 130011012347 |
11 | 50156910947 |
12 | 2124451244b |
13 | c34c25c108 |
14 | 6414b3477d |
15 | 35adcdb682 |
hex | 1e45429cfb |
130011012347 has 2 divisors, whose sum is σ = 130011012348. Its totient is φ = 130011012346.
The previous prime is 130011012301. The next prime is 130011012361. The reversal of 130011012347 is 743210110031.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (743210110031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130011012347 - 210 = 130011011323 is a prime.
It is not a weakly prime, because it can be changed into another prime (130011012377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005506173 + 65005506174.
It is an arithmetic number, because the mean of its divisors is an integer number (65005506174).
Almost surely, 2130011012347 is an apocalyptic number.
130011012347 is a deficient number, since it is larger than the sum of its proper divisors (1).
130011012347 is an equidigital number, since it uses as much as digits as its factorization.
130011012347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 130011012347 its reverse (743210110031), we get a palindrome (873221122378).
The spelling of 130011012347 in words is "one hundred thirty billion, eleven million, twelve thousand, three hundred forty-seven".
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