Base | Representation |
---|---|
bin | 10010111010110100100… |
… | …111100110101001111110 |
3 | 11121021210221002120100102 |
4 | 102322310213212221332 |
5 | 132300111230413342 |
6 | 2433132410001102 |
7 | 162633643045520 |
oct | 22726447465176 |
9 | 4537727076312 |
10 | 1300110404222 |
11 | 46141247a553 |
12 | 18bb78416192 |
13 | 957a4c41796 |
14 | 46cd60c7a10 |
15 | 23c43982832 |
hex | 12eb49e6a7e |
1300110404222 has 32 divisors (see below), whose sum is σ = 2325816364032. Its totient is φ = 532929443904.
The previous prime is 1300110404209. The next prime is 1300110404237. The reversal of 1300110404222 is 2224040110031.
It is a junction number, because it is equal to n+sod(n) for n = 1300110404194 and 1300110404203.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5086178 + ... + 5335674.
It is an arithmetic number, because the mean of its divisors is an integer number (72681761376).
Almost surely, 21300110404222 is an apocalyptic number.
1300110404222 is a deficient number, since it is larger than the sum of its proper divisors (1025705959810).
1300110404222 is a wasteful number, since it uses less digits than its factorization.
1300110404222 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 265712.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 1300110404222 its reverse (2224040110031), we get a palindrome (3524150514253).
The spelling of 1300110404222 in words is "one trillion, three hundred billion, one hundred ten million, four hundred four thousand, two hundred twenty-two".
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