13001120440000 has 560 divisors, whose sum is σ = 40240150030080. Its totient is φ = 4047598080000.

The previous prime is 13001120439961. The next prime is 13001120440027. The reversal of 13001120440000 is 4402110031.

13001120440000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (560).

It is a Harshad number since it is a multiple of its sum of digits (16).

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 3440358111 + ... + 3440361889.

It is an arithmetic number, because the mean of its divisors is an integer number (71857410768).

Almost surely, 2^{13001120440000} is an apocalyptic number.

13001120440000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13001120440000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20120075015040).

13001120440000 is an abundant number, since it is smaller than the sum of its proper divisors (27239029590080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13001120440000 is a wasteful number, since it uses less digits than its factorization.

13001120440000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4946 (or 4921 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 13001120440000 its reverse (4402110031), we get a palindrome (13005522550031).

The spelling of 13001120440000 in words is "thirteen trillion, one billion, one hundred twenty million, four hundred forty thousand".