Search a number
-
+
13001121112 = 237232162877
BaseRepresentation
bin11000001101110110…
…10101110101011000
31020120001220101100011
430012323111311120
5203111241333422
65550031051304
7640115464120
oct140673256530
936501811304
1013001121112
1155718807a1
12262a070b34
1312c26a5095
148b497bc80
155115c4077
hex306ed5d58

13001121112 has 16 divisors (see below), whose sum is σ = 27859545360. Its totient is φ = 5571909024.

The previous prime is 13001121103. The next prime is 13001121121. The reversal of 13001121112 is 21112110031.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (13001121103) and next prime (13001121121).

It is a junction number, because it is equal to n+sod(n) for n = 13001121092 and 13001121101.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 116081383 + ... + 116081494.

It is an arithmetic number, because the mean of its divisors is an integer number (1741221585).

Almost surely, 213001121112 is an apocalyptic number.

It is an amenable number.

13001121112 is an abundant number, since it is smaller than the sum of its proper divisors (14858424248).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13001121112 is a wasteful number, since it uses less digits than its factorization.

13001121112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 232162890 (or 232162886 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 13001121112 its reverse (21112110031), we get a palindrome (34113231143).

The spelling of 13001121112 in words is "thirteen billion, one million, one hundred twenty-one thousand, one hundred twelve".

Divisors: 1 2 4 7 8 14 28 56 232162877 464325754 928651508 1625140139 1857303016 3250280278 6500560556 13001121112