Base | Representation |
---|---|
bin | 1011110100110000111100… |
… | …1101100000001101001111 |
3 | 1201000220011111020112200101 |
4 | 2331030033031200031033 |
5 | 3201002244011444043 |
6 | 43352344351511531 |
7 | 2511204621564022 |
oct | 275141715401517 |
9 | 51026144215611 |
10 | 13001121203023 |
11 | 4162820a87168 |
12 | 155b8552285a7 |
13 | 734001050c65 |
14 | 32d386cc31b9 |
15 | 1782c7d0a24d |
hex | bd30f36034f |
13001121203023 has 2 divisors, whose sum is σ = 13001121203024. Its totient is φ = 13001121203022.
The previous prime is 13001121202933. The next prime is 13001121203033. The reversal of 13001121203023 is 32030212110031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13001121203023 - 241 = 10802097947471 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13001121203033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500560601511 + 6500560601512.
It is an arithmetic number, because the mean of its divisors is an integer number (6500560601512).
Almost surely, 213001121203023 is an apocalyptic number.
13001121203023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13001121203023 is an equidigital number, since it uses as much as digits as its factorization.
13001121203023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 13001121203023 its reverse (32030212110031), we get a palindrome (45031333313054).
The spelling of 13001121203023 in words is "thirteen trillion, one billion, one hundred twenty-one million, two hundred three thousand, twenty-three".
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