Search a number
-
+
1300112332030 = 25130011233203
BaseRepresentation
bin10010111010110100101…
…110111101010011111110
311121021211001201111210201
4102322310232331103332
5132300112224111110
62433132515154114
7162633665325121
oct22726456752376
94537731644721
101300112332030
11461413576986
1218bb78ba593a
13957a54680b5
1446cd646a3b8
1523c43c13b3a
hex12eb4bbd4fe

1300112332030 has 8 divisors (see below), whose sum is σ = 2340202197672. Its totient is φ = 520044932808.

The previous prime is 1300112332019. The next prime is 1300112332063. The reversal of 1300112332030 is 302332110031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1300112331989 and 1300112332007.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65005616592 + ... + 65005616611.

It is an arithmetic number, because the mean of its divisors is an integer number (292525274709).

Almost surely, 21300112332030 is an apocalyptic number.

1300112332030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1300112332030 is a deficient number, since it is larger than the sum of its proper divisors (1040089865642).

1300112332030 is a wasteful number, since it uses less digits than its factorization.

1300112332030 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 130011233210.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 1300112332030 its reverse (302332110031), we get a palindrome (1602444442061).

The spelling of 1300112332030 in words is "one trillion, three hundred billion, one hundred twelve million, three hundred thirty-two thousand, thirty".

Divisors: 1 2 5 10 130011233203 260022466406 650056166015 1300112332030