Base | Representation |
---|---|
bin | 1011110100110000111111… |
… | …1011110001011000110111 |
3 | 1201000220012100001202112121 |
4 | 2331030033323301120313 |
5 | 3201002310113111043 |
6 | 43352345503500411 |
7 | 2511205126641364 |
oct | 275141773613067 |
9 | 51026170052477 |
10 | 13001133332023 |
11 | 4162827910931 |
12 | 155b8592b7707 |
13 | 734003709895 |
14 | 32d38875d46b |
15 | 1782c8e03ded |
hex | bd30fef1637 |
13001133332023 has 4 divisors (see below), whose sum is σ = 13246437734568. Its totient is φ = 12755828929480.
The previous prime is 13001133332009. The next prime is 13001133332149. The reversal of 13001133332023 is 32023333110031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13001133332023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13001133332623) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 122652201193 + ... + 122652201298.
It is an arithmetic number, because the mean of its divisors is an integer number (3311609433642).
Almost surely, 213001133332023 is an apocalyptic number.
13001133332023 is a deficient number, since it is larger than the sum of its proper divisors (245304402545).
13001133332023 is an equidigital number, since it uses as much as digits as its factorization.
13001133332023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 245304402544.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 13001133332023 its reverse (32023333110031), we get a palindrome (45024466442054).
The spelling of 13001133332023 in words is "thirteen trillion, one billion, one hundred thirty-three million, three hundred thirty-two thousand, twenty-three".
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