Base | Representation |
---|---|
bin | 111100100010101001… |
… | …0001011010001100001 |
3 | 110102120201102000022221 |
4 | 1321011102023101201 |
5 | 4112230410132203 |
6 | 135420523431041 |
7 | 12251542523122 |
oct | 1710522132141 |
9 | 412521360287 |
10 | 130011411553 |
11 | 50157063871 |
12 | 21244685481 |
13 | c34c36ba2a |
14 | 6414bda049 |
15 | 35add69abd |
hex | 1e4548b461 |
130011411553 has 8 divisors (see below), whose sum is σ = 133952826600. Its totient is φ = 126125121408.
The previous prime is 130011411539. The next prime is 130011411559. The reversal of 130011411553 is 355114110031.
It can be written as a sum of positive squares in 4 ways, for example, as 694217104 + 129317194449 = 26348^2 + 359607^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130011411553 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130011411559) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13776438 + ... + 13785871.
It is an arithmetic number, because the mean of its divisors is an integer number (16744103325).
Almost surely, 2130011411553 is an apocalyptic number.
It is an amenable number.
130011411553 is a deficient number, since it is larger than the sum of its proper divisors (3941415047).
130011411553 is an equidigital number, since it uses as much as digits as its factorization.
130011411553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27562451.
The product of its (nonzero) digits is 900, while the sum is 25.
Adding to 130011411553 its reverse (355114110031), we get a palindrome (485125521584).
The spelling of 130011411553 in words is "one hundred thirty billion, eleven million, four hundred eleven thousand, five hundred fifty-three".
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