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130012002023 = 472766212809
BaseRepresentation
bin111100100010101010…
…0011011011011100111
3110102120202112000022012
41321011110123123213
54112231033031043
6135420544224435
712251550532451
oct1710524333347
9412522460265
10130012002023
1150157427462
122124490b11b
13c34c517717
146414d112d1
1535ade34a18
hex1e4551b6e7

130012002023 has 4 divisors (see below), whose sum is σ = 132778214880. Its totient is φ = 127245789168.

The previous prime is 130012002013. The next prime is 130012002179. The reversal of 130012002023 is 320200210031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130012002023 - 234 = 112832132839 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130012001989 and 130012002007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130012002013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1383106358 + ... + 1383106451.

It is an arithmetic number, because the mean of its divisors is an integer number (33194553720).

Almost surely, 2130012002023 is an apocalyptic number.

130012002023 is a deficient number, since it is larger than the sum of its proper divisors (2766212857).

130012002023 is an equidigital number, since it uses as much as digits as its factorization.

130012002023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2766212856.

The product of its (nonzero) digits is 72, while the sum is 14.

Adding to 130012002023 its reverse (320200210031), we get a palindrome (450212212054).

The spelling of 130012002023 in words is "one hundred thirty billion, twelve million, two thousand, twenty-three".

Divisors: 1 47 2766212809 130012002023