130012019 has 2 divisors, whose sum is σ = 130012020. Its totient is φ = 130012018.

The previous prime is 130012009. The next prime is 130012033. The reversal of 130012019 is 910210031.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130012019 is a prime.

It is a super-2 number, since 2×130012019² = 33806250168912722, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 130011988 and 130012006.

It is not a weakly prime, because it can be changed into another prime (130012009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006009 + 65006010.

It is an arithmetic number, because the mean of its divisors is an integer number (65006010).

Almost surely, 2^130012019 is an apocalyptic number.

130012019 is a deficient number, since it is larger than the sum of its proper divisors (1).

130012019 is an equidigital number, since it uses as much as digits as its factorization.

130012019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

The square root of 130012019 is about 11402.2813068263. The cubic root of 130012019 is about 506.5953131763.

The spelling of 130012019 in words is "one hundred thirty million, twelve thousand, nineteen".