Base | Representation |
---|---|
bin | 10010111010110101001… |
… | …100111110011111100101 |
3 | 11121021211121112022021001 |
4 | 102322311030332133211 |
5 | 132300121232414224 |
6 | 2433133355553301 |
7 | 162634122241225 |
oct | 22726514763745 |
9 | 4537747468231 |
10 | 1300120201189 |
11 | 461417a61117 |
12 | 18bb7b75b831 |
13 | 957a6c91ac4 |
14 | 46cd7518085 |
15 | 23c4476a544 |
hex | 12eb533e7e5 |
1300120201189 has 2 divisors, whose sum is σ = 1300120201190. Its totient is φ = 1300120201188.
The previous prime is 1300120201183. The next prime is 1300120201307. The reversal of 1300120201189 is 9811020210031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1109299752289 + 190820448900 = 1053233^2 + 436830^2 .
It is a cyclic number.
It is not a de Polignac number, because 1300120201189 - 25 = 1300120201157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1300120201183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650060100594 + 650060100595.
It is an arithmetic number, because the mean of its divisors is an integer number (650060100595).
Almost surely, 21300120201189 is an apocalyptic number.
It is an amenable number.
1300120201189 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300120201189 is an equidigital number, since it uses as much as digits as its factorization.
1300120201189 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864, while the sum is 28.
The spelling of 1300120201189 in words is "one trillion, three hundred billion, one hundred twenty million, two hundred one thousand, one hundred eighty-nine".
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