1300120411 has 2 divisors, whose sum is σ = 1300120412. Its totient is φ = 1300120410.

The previous prime is 1300120397. The next prime is 1300120453. The reversal of 1300120411 is 1140210031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1300120411 - 2¹⁵ = 1300087643 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1300120391 and 1300120400.

It is not a weakly prime, because it can be changed into another prime (1300120711) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650060205 + 650060206.

It is an arithmetic number, because the mean of its divisors is an integer number (650060206).

Almost surely, 2^1300120411 is an apocalyptic number.

1300120411 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300120411 is an equidigital number, since it uses as much as digits as its factorization.

1300120411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 1300120411 is about 36057.1825161090. The cubic root of 1300120411 is about 1091.4265783563.

Adding to 1300120411 its reverse (1140210031), we get a palindrome (2440330442).

The spelling of 1300120411 in words is "one billion, three hundred million, one hundred twenty thousand, four hundred eleven".