Search a number
-
+
13001204331110 = 251300120433111
BaseRepresentation
bin1011110100110001010000…
…1010100111001001100110
31201000220101021122212222102
42331030110022213021212
53201002431302043420
643352400521332102
72511206651265662
oct275142412471146
951026337585872
1013001204331110
1141628639a4566
12155b879037032
13734015338088
1432d393d618a2
151782d027aa75
hexbd3142a7266

13001204331110 has 8 divisors (see below), whose sum is σ = 23402167796016. Its totient is φ = 5200481732440.

The previous prime is 13001204331061. The next prime is 13001204331113. The reversal of 13001204331110 is 1113340210031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13001204331113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 650060216546 + ... + 650060216565.

It is an arithmetic number, because the mean of its divisors is an integer number (2925270974502).

Almost surely, 213001204331110 is an apocalyptic number.

13001204331110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13001204331110 is a deficient number, since it is larger than the sum of its proper divisors (10400963464906).

13001204331110 is a wasteful number, since it uses less digits than its factorization.

13001204331110 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1300120433118.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 13001204331110 its reverse (1113340210031), we get a palindrome (14114544541141).

The spelling of 13001204331110 in words is "thirteen trillion, one billion, two hundred four million, three hundred thirty-one thousand, one hundred ten".

Divisors: 1 2 5 10 1300120433111 2600240866222 6500602165555 13001204331110