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130012083458 = 265006041729
BaseRepresentation
bin111100100010101010…
…0101111010100000010
3110102120202200011000022
41321011110233110002
54112231043132313
6135420550053442
712251551322045
oct1710524572402
9412522604008
10130012083458
1150157482664
122124494a282
13c34c5457ca
146414d32c5c
1535ade4dc08
hex1e4552f502

130012083458 has 4 divisors (see below), whose sum is σ = 195018125190. Its totient is φ = 65006041728.

The previous prime is 130012083457. The next prime is 130012083469. The reversal of 130012083458 is 854380210031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 854380210031 = 5914481020509.

It can be written as a sum of positive squares in only one way, i.e., 128216273329 + 1795810129 = 358073^2 + 42377^2 .

It is not an unprimeable number, because it can be changed into a prime (130012083457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32503020863 + ... + 32503020866.

Almost surely, 2130012083458 is an apocalyptic number.

130012083458 is a deficient number, since it is larger than the sum of its proper divisors (65006041732).

130012083458 is an equidigital number, since it uses as much as digits as its factorization.

130012083458 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65006041731.

The product of its (nonzero) digits is 23040, while the sum is 35.

Adding to 130012083458 its reverse (854380210031), we get a palindrome (984392293489).

The spelling of 130012083458 in words is "one hundred thirty billion, twelve million, eighty-three thousand, four hundred fifty-eight".

Divisors: 1 2 65006041729 130012083458