Base | Representation |
---|---|
bin | 111100100010101010… |
… | …0101111010100000010 |
3 | 110102120202200011000022 |
4 | 1321011110233110002 |
5 | 4112231043132313 |
6 | 135420550053442 |
7 | 12251551322045 |
oct | 1710524572402 |
9 | 412522604008 |
10 | 130012083458 |
11 | 50157482664 |
12 | 2124494a282 |
13 | c34c5457ca |
14 | 6414d32c5c |
15 | 35ade4dc08 |
hex | 1e4552f502 |
130012083458 has 4 divisors (see below), whose sum is σ = 195018125190. Its totient is φ = 65006041728.
The previous prime is 130012083457. The next prime is 130012083469. The reversal of 130012083458 is 854380210031.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 854380210031 = 59 ⋅14481020509.
It can be written as a sum of positive squares in only one way, i.e., 128216273329 + 1795810129 = 358073^2 + 42377^2 .
It is not an unprimeable number, because it can be changed into a prime (130012083457) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32503020863 + ... + 32503020866.
Almost surely, 2130012083458 is an apocalyptic number.
130012083458 is a deficient number, since it is larger than the sum of its proper divisors (65006041732).
130012083458 is an equidigital number, since it uses as much as digits as its factorization.
130012083458 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65006041731.
The product of its (nonzero) digits is 23040, while the sum is 35.
Adding to 130012083458 its reverse (854380210031), we get a palindrome (984392293489).
The spelling of 130012083458 in words is "one hundred thirty billion, twelve million, eighty-three thousand, four hundred fifty-eight".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.121 sec. • engine limits •