Base | Representation |
---|---|
bin | 111100100010101010… |
… | …0101111010100000001 |
3 | 110102120202200011000021 |
4 | 1321011110233110001 |
5 | 4112231043132312 |
6 | 135420550053441 |
7 | 12251551322044 |
oct | 1710524572401 |
9 | 412522604007 |
10 | 130012083457 |
11 | 50157482663 |
12 | 2124494a281 |
13 | c34c5457c9 |
14 | 6414d32c5b |
15 | 35ade4dc07 |
hex | 1e4552f501 |
130012083457 has 2 divisors, whose sum is σ = 130012083458. Its totient is φ = 130012083456.
The previous prime is 130012083437. The next prime is 130012083469. The reversal of 130012083457 is 754380210031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 128118180096 + 1893903361 = 357936^2 + 43519^2 .
It is a cyclic number.
It is not a de Polignac number, because 130012083457 - 27 = 130012083329 is a prime.
It is not a weakly prime, because it can be changed into another prime (130012083437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006041728 + 65006041729.
It is an arithmetic number, because the mean of its divisors is an integer number (65006041729).
Almost surely, 2130012083457 is an apocalyptic number.
It is an amenable number.
130012083457 is a deficient number, since it is larger than the sum of its proper divisors (1).
130012083457 is an equidigital number, since it uses as much as digits as its factorization.
130012083457 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 34.
Adding to 130012083457 its reverse (754380210031), we get a palindrome (884392293488).
The spelling of 130012083457 in words is "one hundred thirty billion, twelve million, eighty-three thousand, four hundred fifty-seven".
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